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  1. Countable products and countable direct sums of compact metrizable spaces in the absence of the Axiom of Choice.Kyriakos Keremedis, Eleftherios Tachtsis & Eliza Wajch - 2023 - Annals of Pure and Applied Logic 174 (7):103283.
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  • Notions of compactness for special subsets of ℝ I and some weak forms of the axiom of choice.Marianne Morillon - 2010 - Journal of Symbolic Logic 75 (1):255-268.
    We work in set-theory without choice ZF. A set is Countable if it is finite or equipotent with ${\Bbb N}$ . Given a closed subset F of [0, 1] I which is a bounded subset of $\ell ^{1}(I)$ (resp. such that $F\subseteq c_{0}(I)$ ), we show that the countable axiom of choice for finite sets, (resp. the countable axiom of choice AC N ) implies that F is compact. This enhances previous results where AC N (resp. the axiom of Dependent (...)
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  • Consequences of the failure of the axiom of choice in the theory of Lindelof metric spaces.Kyriakos Keremedis - 2004 - Mathematical Logic Quarterly 50 (2):141.
    We study within the framework of Zermelo-Fraenkel set theory ZF the role that the axiom of choice plays in the theory of Lindelöf metric spaces. We show that in ZF the weak choice principles: Every Lindelöf metric space is separable and Every Lindelöf metric space is second countable are equivalent. We also prove that a Lindelöf metric space is hereditarily separable iff it is hereditarily Lindelöf iff it hold as well the axiom of choice restricted to countable sets and to (...)
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  • Compact and Loeb Hausdorff spaces in equation image and the axiom of choice for families of finite sets.Kyriakos Keremedis - 2012 - Mathematical Logic Quarterly 58 (3):130-138.
    Given a set X, equation image denotes the statement: “equation image has a choice set” and equation image denotes the family of all closed subsets of the topological space equation image whose definition depends on a finite subset of X. We study the interrelations between the statements equation image equation image equation image equation image and “equation imagehas a choice set”. We show: equation image iff equation image iff equation image has a choice set iff equation image. equation image iff (...)
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