There is no standard model of ZFC

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Abstract
Main results are:(i) Let M_st be standard model of ZFC. Then ~Con(ZFC+∃M_st), (ii) let k be an inaccessible cardinal then ~Con(ZFC+∃k),[10],11].
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First archival date: 2017-12-24
Latest version: 3 (2019-07-06)
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2017-12-24

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